3.1.26 \(\int \frac {(d-c^2 d x^2)^3 (a+b \text {ArcSin}(c x))}{x^3} \, dx\) [26]

Optimal. Leaf size=263 \[ \frac {3}{32} b c^3 d^3 x \sqrt {1-c^2 x^2}-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}+\frac {3}{32} b c^2 d^3 \text {ArcSin}(c x)-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) (a+b \text {ArcSin}(c x))-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 (a+b \text {ArcSin}(c x))-\frac {d^3 \left (1-c^2 x^2\right )^3 (a+b \text {ArcSin}(c x))}{2 x^2}+\frac {3 i c^2 d^3 (a+b \text {ArcSin}(c x))^2}{2 b}-3 c^2 d^3 (a+b \text {ArcSin}(c x)) \log \left (1-e^{2 i \text {ArcSin}(c x)}\right )+\frac {3}{2} i b c^2 d^3 \text {PolyLog}\left (2,e^{2 i \text {ArcSin}(c x)}\right ) \]

[Out]

-7/16*b*c^3*d^3*x*(-c^2*x^2+1)^(3/2)-1/2*b*c*d^3*(-c^2*x^2+1)^(5/2)/x+3/32*b*c^2*d^3*arcsin(c*x)-3/2*c^2*d^3*(
-c^2*x^2+1)*(a+b*arcsin(c*x))-3/4*c^2*d^3*(-c^2*x^2+1)^2*(a+b*arcsin(c*x))-1/2*d^3*(-c^2*x^2+1)^3*(a+b*arcsin(
c*x))/x^2+3/2*I*c^2*d^3*(a+b*arcsin(c*x))^2/b-3*c^2*d^3*(a+b*arcsin(c*x))*ln(1-(I*c*x+(-c^2*x^2+1)^(1/2))^2)+3
/2*I*b*c^2*d^3*polylog(2,(I*c*x+(-c^2*x^2+1)^(1/2))^2)+3/32*b*c^3*d^3*x*(-c^2*x^2+1)^(1/2)

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Rubi [A]
time = 0.22, antiderivative size = 263, normalized size of antiderivative = 1.00, number of steps used = 17, number of rules used = 10, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {4775, 283, 201, 222, 4773, 4721, 3798, 2221, 2317, 2438} \begin {gather*} -\frac {d^3 \left (1-c^2 x^2\right )^3 (a+b \text {ArcSin}(c x))}{2 x^2}-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 (a+b \text {ArcSin}(c x))-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) (a+b \text {ArcSin}(c x))+\frac {3 i c^2 d^3 (a+b \text {ArcSin}(c x))^2}{2 b}-3 c^2 d^3 \log \left (1-e^{2 i \text {ArcSin}(c x)}\right ) (a+b \text {ArcSin}(c x))+\frac {3}{2} i b c^2 d^3 \text {Li}_2\left (e^{2 i \text {ArcSin}(c x)}\right )+\frac {3}{32} b c^2 d^3 \text {ArcSin}(c x)-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}+\frac {3}{32} b c^3 d^3 x \sqrt {1-c^2 x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((d - c^2*d*x^2)^3*(a + b*ArcSin[c*x]))/x^3,x]

[Out]

(3*b*c^3*d^3*x*Sqrt[1 - c^2*x^2])/32 - (7*b*c^3*d^3*x*(1 - c^2*x^2)^(3/2))/16 - (b*c*d^3*(1 - c^2*x^2)^(5/2))/
(2*x) + (3*b*c^2*d^3*ArcSin[c*x])/32 - (3*c^2*d^3*(1 - c^2*x^2)*(a + b*ArcSin[c*x]))/2 - (3*c^2*d^3*(1 - c^2*x
^2)^2*(a + b*ArcSin[c*x]))/4 - (d^3*(1 - c^2*x^2)^3*(a + b*ArcSin[c*x]))/(2*x^2) + (((3*I)/2)*c^2*d^3*(a + b*A
rcSin[c*x])^2)/b - 3*c^2*d^3*(a + b*ArcSin[c*x])*Log[1 - E^((2*I)*ArcSin[c*x])] + ((3*I)/2)*b*c^2*d^3*PolyLog[
2, E^((2*I)*ArcSin[c*x])]

Rule 201

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[x*((a + b*x^n)^p/(n*p + 1)), x] + Dist[a*n*(p/(n*p + 1)),
Int[(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && GtQ[p, 0] && (IntegerQ[2*p] || (EqQ[n, 2
] && IntegerQ[4*p]) || (EqQ[n, 2] && IntegerQ[3*p]) || LtQ[Denominator[p + 1/n], Denominator[p]])

Rule 222

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt[a])]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 283

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^p/(c*(m + 1
))), x] - Dist[b*n*(p/(c^n*(m + 1))), Int[(c*x)^(m + n)*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c}, x] &&
IGtQ[n, 0] && GtQ[p, 0] && LtQ[m, -1] &&  !ILtQ[(m + n*p + n + 1)/n, 0] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 2221

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
(f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x]
- Dist[d*(m/(b*f*g*n*Log[F])), Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2317

Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Dist[1/(d*e*n*Log[F]), Subst[Int
[Log[a + b*x]/x, x], x, (F^(e*(c + d*x)))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 3798

Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Simp[I*((c + d*x)^(m + 1)/(d*(
m + 1))), x] - Dist[2*I, Int[(c + d*x)^m*E^(2*I*k*Pi)*(E^(2*I*(e + f*x))/(1 + E^(2*I*k*Pi)*E^(2*I*(e + f*x))))
, x], x] /; FreeQ[{c, d, e, f}, x] && IntegerQ[4*k] && IGtQ[m, 0]

Rule 4721

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/(x_), x_Symbol] :> Subst[Int[(a + b*x)^n*Cot[x], x], x, ArcSin[c*
x]] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0]

Rule 4773

Int[(((a_.) + ArcSin[(c_.)*(x_)]*(b_.))*((d_) + (e_.)*(x_)^2)^(p_.))/(x_), x_Symbol] :> Simp[(d + e*x^2)^p*((a
+ b*ArcSin[c*x])/(2*p)), x] + (Dist[d, Int[(d + e*x^2)^(p - 1)*((a + b*ArcSin[c*x])/x), x], x] - Dist[b*c*(d^
p/(2*p)), Int[(1 - c^2*x^2)^(p - 1/2), x], x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0]

Rule 4775

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(f*x)^
(m + 1)*(d + e*x^2)^p*((a + b*ArcSin[c*x])/(f*(m + 1))), x] + (-Dist[b*c*(d^p/(f*(m + 1))), Int[(f*x)^(m + 1)*
(1 - c^2*x^2)^(p - 1/2), x], x] - Dist[2*e*(p/(f^2*(m + 1))), Int[(f*x)^(m + 2)*(d + e*x^2)^(p - 1)*(a + b*Arc
Sin[c*x]), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0] && ILtQ[(m + 1)/2, 0]

Rubi steps

\begin {align*} \int \frac {\left (d-c^2 d x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{x^3} \, dx &=-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}-\left (3 c^2 d\right ) \int \frac {\left (d-c^2 d x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )}{x} \, dx+\frac {1}{2} \left (b c d^3\right ) \int \frac {\left (1-c^2 x^2\right )^{5/2}}{x^2} \, dx\\ &=-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}-\left (3 c^2 d^2\right ) \int \frac {\left (d-c^2 d x^2\right ) \left (a+b \sin ^{-1}(c x)\right )}{x} \, dx+\frac {1}{4} \left (3 b c^3 d^3\right ) \int \left (1-c^2 x^2\right )^{3/2} \, dx-\frac {1}{2} \left (5 b c^3 d^3\right ) \int \left (1-c^2 x^2\right )^{3/2} \, dx\\ &=-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}-\left (3 c^2 d^3\right ) \int \frac {a+b \sin ^{-1}(c x)}{x} \, dx+\frac {1}{16} \left (9 b c^3 d^3\right ) \int \sqrt {1-c^2 x^2} \, dx+\frac {1}{2} \left (3 b c^3 d^3\right ) \int \sqrt {1-c^2 x^2} \, dx-\frac {1}{8} \left (15 b c^3 d^3\right ) \int \sqrt {1-c^2 x^2} \, dx\\ &=\frac {3}{32} b c^3 d^3 x \sqrt {1-c^2 x^2}-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}-\left (3 c^2 d^3\right ) \text {Subst}\left (\int (a+b x) \cot (x) \, dx,x,\sin ^{-1}(c x)\right )+\frac {1}{32} \left (9 b c^3 d^3\right ) \int \frac {1}{\sqrt {1-c^2 x^2}} \, dx+\frac {1}{4} \left (3 b c^3 d^3\right ) \int \frac {1}{\sqrt {1-c^2 x^2}} \, dx-\frac {1}{16} \left (15 b c^3 d^3\right ) \int \frac {1}{\sqrt {1-c^2 x^2}} \, dx\\ &=\frac {3}{32} b c^3 d^3 x \sqrt {1-c^2 x^2}-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}+\frac {3}{32} b c^2 d^3 \sin ^{-1}(c x)-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac {3 i c^2 d^3 \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}+\left (6 i c^2 d^3\right ) \text {Subst}\left (\int \frac {e^{2 i x} (a+b x)}{1-e^{2 i x}} \, dx,x,\sin ^{-1}(c x)\right )\\ &=\frac {3}{32} b c^3 d^3 x \sqrt {1-c^2 x^2}-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}+\frac {3}{32} b c^2 d^3 \sin ^{-1}(c x)-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac {3 i c^2 d^3 \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}-3 c^2 d^3 \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )+\left (3 b c^2 d^3\right ) \text {Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )\\ &=\frac {3}{32} b c^3 d^3 x \sqrt {1-c^2 x^2}-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}+\frac {3}{32} b c^2 d^3 \sin ^{-1}(c x)-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac {3 i c^2 d^3 \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}-3 c^2 d^3 \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-\frac {1}{2} \left (3 i b c^2 d^3\right ) \text {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{2 i \sin ^{-1}(c x)}\right )\\ &=\frac {3}{32} b c^3 d^3 x \sqrt {1-c^2 x^2}-\frac {7}{16} b c^3 d^3 x \left (1-c^2 x^2\right )^{3/2}-\frac {b c d^3 \left (1-c^2 x^2\right )^{5/2}}{2 x}+\frac {3}{32} b c^2 d^3 \sin ^{-1}(c x)-\frac {3}{2} c^2 d^3 \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac {3}{4} c^2 d^3 \left (1-c^2 x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )-\frac {d^3 \left (1-c^2 x^2\right )^3 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac {3 i c^2 d^3 \left (a+b \sin ^{-1}(c x)\right )^2}{2 b}-3 c^2 d^3 \left (a+b \sin ^{-1}(c x)\right ) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )+\frac {3}{2} i b c^2 d^3 \text {Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )\\ \end {align*}

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Mathematica [A]
time = 0.13, size = 226, normalized size = 0.86 \begin {gather*} -\frac {d^3 \left (16 a-48 a c^4 x^4+8 a c^6 x^6+16 b c x \sqrt {1-c^2 x^2}-21 b c^3 x^3 \sqrt {1-c^2 x^2}+2 b c^5 x^5 \sqrt {1-c^2 x^2}-48 i b c^2 x^2 \text {ArcSin}(c x)^2+42 b c^2 x^2 \text {ArcTan}\left (\frac {c x}{-1+\sqrt {1-c^2 x^2}}\right )+8 b \text {ArcSin}(c x) \left (2-6 c^4 x^4+c^6 x^6+12 c^2 x^2 \log \left (1-e^{2 i \text {ArcSin}(c x)}\right )\right )+96 a c^2 x^2 \log (x)-48 i b c^2 x^2 \text {PolyLog}\left (2,e^{2 i \text {ArcSin}(c x)}\right )\right )}{32 x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((d - c^2*d*x^2)^3*(a + b*ArcSin[c*x]))/x^3,x]

[Out]

-1/32*(d^3*(16*a - 48*a*c^4*x^4 + 8*a*c^6*x^6 + 16*b*c*x*Sqrt[1 - c^2*x^2] - 21*b*c^3*x^3*Sqrt[1 - c^2*x^2] +
2*b*c^5*x^5*Sqrt[1 - c^2*x^2] - (48*I)*b*c^2*x^2*ArcSin[c*x]^2 + 42*b*c^2*x^2*ArcTan[(c*x)/(-1 + Sqrt[1 - c^2*
x^2])] + 8*b*ArcSin[c*x]*(2 - 6*c^4*x^4 + c^6*x^6 + 12*c^2*x^2*Log[1 - E^((2*I)*ArcSin[c*x])]) + 96*a*c^2*x^2*
Log[x] - (48*I)*b*c^2*x^2*PolyLog[2, E^((2*I)*ArcSin[c*x])]))/x^2

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Maple [A]
time = 0.48, size = 306, normalized size = 1.16

method	result	size
derivativedivides	\(c^{2} \left (-\frac {d^{3} a \,c^{4} x^{4}}{4}+\frac {3 d^{3} a \,c^{2} x^{2}}{2}-\frac {d^{3} a}{2 c^{2} x^{2}}-3 d^{3} a \ln \left (c x \right )+\frac {3 i b \,d^{3} \arcsin \left (c x \right )^{2}}{2}+\frac {5 b c \,d^{3} x \sqrt {-c^{2} x^{2}+1}}{8}+\frac {5 d^{3} b \arcsin \left (c x \right ) c^{2} x^{2}}{4}-\frac {5 b \,d^{3} \arcsin \left (c x \right )}{8}+3 i d^{3} b \polylog \left (2, -i c x -\sqrt {-c^{2} x^{2}+1}\right )-\frac {d^{3} b \sqrt {-c^{2} x^{2}+1}}{2 c x}-\frac {d^{3} b \arcsin \left (c x \right )}{2 c^{2} x^{2}}-3 d^{3} b \arcsin \left (c x \right ) \ln \left (1+i c x +\sqrt {-c^{2} x^{2}+1}\right )-3 d^{3} b \arcsin \left (c x \right ) \ln \left (1-i c x -\sqrt {-c^{2} x^{2}+1}\right )+3 i d^{3} b \polylog \left (2, i c x +\sqrt {-c^{2} x^{2}+1}\right )+\frac {i d^{3} b}{2}-\frac {d^{3} b \arcsin \left (c x \right ) \cos \left (4 \arcsin \left (c x \right )\right )}{32}+\frac {d^{3} b \sin \left (4 \arcsin \left (c x \right )\right )}{128}\right )\)	\(306\)
default	\(c^{2} \left (-\frac {d^{3} a \,c^{4} x^{4}}{4}+\frac {3 d^{3} a \,c^{2} x^{2}}{2}-\frac {d^{3} a}{2 c^{2} x^{2}}-3 d^{3} a \ln \left (c x \right )+\frac {3 i b \,d^{3} \arcsin \left (c x \right )^{2}}{2}+\frac {5 b c \,d^{3} x \sqrt {-c^{2} x^{2}+1}}{8}+\frac {5 d^{3} b \arcsin \left (c x \right ) c^{2} x^{2}}{4}-\frac {5 b \,d^{3} \arcsin \left (c x \right )}{8}+3 i d^{3} b \polylog \left (2, -i c x -\sqrt {-c^{2} x^{2}+1}\right )-\frac {d^{3} b \sqrt {-c^{2} x^{2}+1}}{2 c x}-\frac {d^{3} b \arcsin \left (c x \right )}{2 c^{2} x^{2}}-3 d^{3} b \arcsin \left (c x \right ) \ln \left (1+i c x +\sqrt {-c^{2} x^{2}+1}\right )-3 d^{3} b \arcsin \left (c x \right ) \ln \left (1-i c x -\sqrt {-c^{2} x^{2}+1}\right )+3 i d^{3} b \polylog \left (2, i c x +\sqrt {-c^{2} x^{2}+1}\right )+\frac {i d^{3} b}{2}-\frac {d^{3} b \arcsin \left (c x \right ) \cos \left (4 \arcsin \left (c x \right )\right )}{32}+\frac {d^{3} b \sin \left (4 \arcsin \left (c x \right )\right )}{128}\right )\)	\(306\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-c^2*d*x^2+d)^3*(a+b*arcsin(c*x))/x^3,x,method=_RETURNVERBOSE)

[Out]

c^2*(-1/4*d^3*a*c^4*x^4+3/2*d^3*a*c^2*x^2-1/2*d^3*a/c^2/x^2-3*d^3*a*ln(c*x)+3/2*I*d^3*b*arcsin(c*x)^2+5/8*b*c*
d^3*x*(-c^2*x^2+1)^(1/2)+5/4*d^3*b*arcsin(c*x)*c^2*x^2-5/8*b*d^3*arcsin(c*x)+3*I*d^3*b*polylog(2,-I*c*x-(-c^2*
x^2+1)^(1/2))-1/2*d^3*b/c/x*(-c^2*x^2+1)^(1/2)-1/2*d^3*b*arcsin(c*x)/c^2/x^2-3*d^3*b*arcsin(c*x)*ln(1+I*c*x+(-
c^2*x^2+1)^(1/2))-3*d^3*b*arcsin(c*x)*ln(1-I*c*x-(-c^2*x^2+1)^(1/2))+1/2*I*d^3*b+3*I*d^3*b*polylog(2,I*c*x+(-c
^2*x^2+1)^(1/2))-1/32*d^3*b*arcsin(c*x)*cos(4*arcsin(c*x))+1/128*d^3*b*sin(4*arcsin(c*x)))

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c^2*d*x^2+d)^3*(a+b*arcsin(c*x))/x^3,x, algorithm="maxima")

[Out]

-1/4*a*c^6*d^3*x^4 + 3/2*a*c^4*d^3*x^2 - 3*a*c^2*d^3*log(x) - 1/2*b*d^3*(sqrt(-c^2*x^2 + 1)*c/x + arcsin(c*x)/
x^2) - 1/2*a*d^3/x^2 - integrate((b*c^6*d^3*x^4 - 3*b*c^4*d^3*x^2 + 3*b*c^2*d^3)*arctan2(c*x, sqrt(c*x + 1)*sq
rt(-c*x + 1))/x, x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c^2*d*x^2+d)^3*(a+b*arcsin(c*x))/x^3,x, algorithm="fricas")

[Out]

integral(-(a*c^6*d^3*x^6 - 3*a*c^4*d^3*x^4 + 3*a*c^2*d^3*x^2 - a*d^3 + (b*c^6*d^3*x^6 - 3*b*c^4*d^3*x^4 + 3*b*
c^2*d^3*x^2 - b*d^3)*arcsin(c*x))/x^3, x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - d^{3} \left (\int \left (- \frac {a}{x^{3}}\right )\, dx + \int \frac {3 a c^{2}}{x}\, dx + \int \left (- 3 a c^{4} x\right )\, dx + \int a c^{6} x^{3}\, dx + \int \left (- \frac {b \operatorname {asin}{\left (c x \right )}}{x^{3}}\right )\, dx + \int \frac {3 b c^{2} \operatorname {asin}{\left (c x \right )}}{x}\, dx + \int \left (- 3 b c^{4} x \operatorname {asin}{\left (c x \right )}\right )\, dx + \int b c^{6} x^{3} \operatorname {asin}{\left (c x \right )}\, dx\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c**2*d*x**2+d)**3*(a+b*asin(c*x))/x**3,x)

[Out]

-d**3*(Integral(-a/x**3, x) + Integral(3*a*c**2/x, x) + Integral(-3*a*c**4*x, x) + Integral(a*c**6*x**3, x) +
Integral(-b*asin(c*x)/x**3, x) + Integral(3*b*c**2*asin(c*x)/x, x) + Integral(-3*b*c**4*x*asin(c*x), x) + Inte
gral(b*c**6*x**3*asin(c*x), x))

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c^2*d*x^2+d)^3*(a+b*arcsin(c*x))/x^3,x, algorithm="giac")

[Out]

integrate(-(c^2*d*x^2 - d)^3*(b*arcsin(c*x) + a)/x^3, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )\,{\left (d-c^2\,d\,x^2\right )}^3}{x^3} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*asin(c*x))*(d - c^2*d*x^2)^3)/x^3,x)

[Out]

int(((a + b*asin(c*x))*(d - c^2*d*x^2)^3)/x^3, x)

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